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MERITROOT FREE LEARNING · CLASS 10 / MATHEMATICS

Areas Related to Circles

Your chapter workspace for understanding concepts, revising key ideas and practising questions. Choose an available resource below.

PYQs6Formulae4Derivations2
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PYQs

Practise questions grouped by chapter and source year.

Practice questions are organised using the years and labels in our source collection. Work through the solutions with your teacher; these are not a complete official examination paper.

Practice question 1

Source year: 20252 marks

Area of sector with radius 6cm, angle 60°. [CBSE 2025]

Practice question 2

Source year: 20243 marks

Horse tied to corner of 15m square by 7m rope. [CBSE 2024]

Practice question 3

Source year: 20252 marks

Find area of sector of circle with radius 6cm and central angle 60°. [CBSE 2025]

Practice question 4

Source year: 20243 marks

A horse is tied to one corner of square plot of side 15m by rope 7m long. Find area it can graze. [CBSE 2024]

Practice question 5

Source year: 20233 marks

Find perimeter of shaded region if ABCD is square of side 14cm and semicircles are drawn on each side. [CBSE 2023]

Practice question 6

Source year: 20222 marks

Area of circle is 154cm². Find circumference. [CBSE 2022]

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Formulae

Revisit important relationships and quick revision formulae.

Sector Area

A = (θ/360) × πr²

Circle Formulas

Area = πr²\nCircumference = 2πr\nDiameter = 2r

Sector Formulas

Area of sector = (θ/360°) × πr²\nLength of arc = (θ/360°) × 2πr\nwhere θ is central angle in degrees

Segment Formulas

Area of segment = Area of sector - Area of triangle

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Derivations

Work through the reasoning behind key concepts.

Sector Area Formula

Area of full circle = πr² for angle 360°. For sector with angle θ°, area is proportional: Area = (θ/360°) × πr². Similarly, arc length = (θ/360°) × 2πr.

Sector Area Derivation

Area of full circle = πr² for 360°\nFor angle θ°: Area = (θ/360) × πr²

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