PYQs
Practise questions grouped by chapter and source year.
Practice questions are organised using the years and labels in our source collection. Work through the solutions with your teacher; these are not a complete official examination paper.
Practice question 1
Source year: 20253 marksTwo resistors of 4Ω and 6Ω are connected in parallel. This combination is connected in series with a 3Ω resistor. Calculate the equivalent resistance of the circuit. [CBSE 2025]
Practice question 2
Source year: 20243 marksAn electric bulb is rated 220V, 100W. Calculate: (a) its resistance (b) current flowing through it when connected to 220V supply. [CBSE 2024]
Practice question 3
Source year: 20235 marksState Ohm's law. Draw a circuit diagram to verify it experimentally. Draw the V-I graph for a conductor obeying Ohm's law. [CBSE 2023]
Practice question 4
Source year: 20222 marksAn electric iron consumes energy at the rate of 840W when the current of 7A flows through it. Calculate the resistance and voltage of the electric iron. [CBSE 2022]
Practice question 5
Source year: 20213 marksHow much current will an electric heater of 1000W draw from a 250V supply line? What should be the resistance of the heater? [CBSE 2021]
Formulae
Revisit important relationships and quick revision formulae.
Ohm's Law
V = IR V = Potential difference (Volts) I = Current (Amperes) R = Resistance (Ohms)
Electric Power
P = VI = I²R = V²/R P = Power (Watts)
Electric Energy
E = P × t = VIt E = Energy (Joules or kWh) 1 kWh = 3.6 × 10⁶ J = 1 Unit
Resistors in Series
R_s = R₁ + R₂ + R₃ + ... Current same, voltage divides
Resistors in Parallel
1/R_p = 1/R₁ + 1/R₂ + 1/R₃ + ... Voltage same, current divides
Heating Effect (Joule's Law)
H = I²Rt = VIt = V²t/R H = Heat produced (Joules)
Derivations
Work through the reasoning behind key concepts.
Ohm's Law Derivation
Consider drift velocity v_d = eEτ/m Current I = neAv_d Substituting and simplifying: V = IR, where R = mL/(ne²Aτ)
Series Resistance
In series: Same current I flows through all V = V₁ + V₂ + V₃ IR = IR₁ + IR₂ + IR₃ R = R₁ + R₂ + R₃
Parallel Resistance
In parallel: Same voltage V across all I = I₁ + I₂ + I₃ V/R = V/R₁ + V/R₂ + V/R₃ 1/R = 1/R₁ + 1/R₂ + 1/R₃
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